-2.5x^2+12x-3.95=0

Solution for -2.5x^2+12x-3.95=0 equation:

-2.5x^2+12x-3.95=0

a = -2.5; b = 12; c = -3.95;
Δ = b2-4ac
Δ = 122-4·(-2.5)·(-3.95)
Δ = 104.5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-\sqrt{104.5}}{2*-2.5}=\frac{-12-\sqrt{104.5}}{-5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+\sqrt{104.5}}{2*-2.5}=\frac{-12+\sqrt{104.5}}{-5}
$